Wednesday, September 5, 2007

Problem of the Week #4

Consider the sequence: 3, 7, 11, 15, 19,...

What would be the next three terms in the sequence? Can you write an algebraic rule to determine any term of the sequence? If so, what would be the 50th term of the sequence?

62 comments:

daniel g said...

it's kind of obvious its going to be at least over 110

daniel g said...

and all you have to do is keep on adding four to each number

Jonah Adler said...

just add 4 every time for the first part

redsoxerman101 said...
This comment has been removed by the author.
Benjamin K. said...
This comment has been removed by the author.
adam said...

the algebraic equation is (n+4).4=x

Danny said...

i agree with daniel g

daniel g said...

i have to agree with adam on it

adam said...

it will be definitely 200

Benjamin K. said...

i think it has to be over 100

daniel g said...

ya josh though you are right it is barely over 200

Danny said...

i agree with daniel g

Benjamin K. said...

i also agree

Jonah Adler said...

i agree with adam on the algebraic equation

daniel g said...

i think i already got the answer

adam said...

never mind i meant to say at least 200

Danny said...

AGAIN

Tova said...

well 50 times 4 is 200 so of course it's over 100

Benjamin K. said...

so did i

Benjamin K. said...

so

Benjamin K. said...

adam i agree with u

daniel g said...

it cant be more than 230 though but cant be less than 200

adam said...

(3+4)*50=aaa

Justin said...

i agree

Jonah Adler said...

i think daniel g is right

adam said...

another equation is 3+(49*)

Jonthan said...

i also agree with adam

Jonah Adler said...

i also agree with adam

Benjamin K. said...

true true very true

Benjamin K. said...

just messing around

Benjamin K. said...

but i do agree

Danny said...

n+4 is the algebraic equation

daniel g said...

well actually the answer is going to be less than 210

Danny said...

true dat true dat

joshredsox said...
This comment has been removed by the author.
joey said...

hi jonthan

daniel g said...

i think the answer is between 200 and 205

joshredsox said...

that little 3 foot 1 grasshopper

joshredsox said...

is always right
i agree with him

joshredsox said...

never mind
he is 3 foot 2 and he is still always right

daniel g said...

josh just stop talking okay!!!!!!!!!!

joshredsox said...

no i won't spot talking

daniel g said...

ill come over there if u dont stop talking

Danny said...

u both shut up

adam said...

josh spelled stop wrong haha

joshredsox said...
This comment has been removed by the author.
joey said...

i think it is whatever adam says is right

daniel g said...

y dont u shutup danny

joey said...

hi josh

joey said...

danny doesnt want to shut up

adam said...

i think the answer is 199 because i'm the 3 foot 2 grasshopper

daniel g said...

well ill make him shutup

Danny said...

meanie pants

joey said...

hi danny

joey said...

hhhhhhhhhhhhiiiiiiiiiiiiii

daniel g said...

WWWWEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Danny said...

shut up daniel

Rachel T said...

I have two comments:
1. all you boys that are getting really goofy and off-topic on this blog are going to be removed from it if you don't watch it.

This is forum for sharing ideas, not for being silly!

2. I haven't heard ANY meaningful discussion of the possible algebraic expression... you might want to think for yourselves instead of spending all your energy agreeing with Adam (even if you do!) So far, I don't see an algebraic expression that works for the terms you have listed already, much less for the future terms of this sequence.

Mrs. Topper said...

that last comment was NOT from Rachel, it was from me!

jeremy said...

yea, this is a blog, not a chat room

Mrs. Topper said...

Jessie,
one way to think about making an algebraic expression is to make a chart with the information that you know.
So, in this case you could have a chart with the term # on one line and the actual term of the sequence below it on the next line.

Then look to see how to get from one to the other.

Example:
1 - 2 - 3 - 4 - 5 -
3 - 7 - 11- 13- 19-
What SAME set of mathematical operation(s) can you do to 1 to get 3 that you can do to 2 and get 7?

daniel g said...

all you have to do is keep on adding four to each number and you'll get it sooner or later